USES drills

A shop usually USES drills and cylinders to make a large diameter hole. Consider, for example, a 15-horsepower vertical machining center that USES this method to make a three-inch deep hole in a 4-inch diameter.

The store takes a rotating 1.25 inch diameter drill to the first part and only takes 1.5 minutes. Next, it takes more time to run a circular interpolation using an inch diameter end milling cutter with indexable bits. The parameters of this tool are 0.1 inch deep cut, 0.7 inch wide cutting, speed of 2300 RPM and feed rate of 25 ipm. The total cycle time of the loop interpolation is 35 to 45 minutes, so the total cycle time for both tools can be assumed to be 45 minutes.

Now consider the same hole in the same machine with the spiral interpolation. One possible tool is a round shell milling cutter with a diameter of 2 inches. The analysis USES the quad-flute, 1/2-inch integrated circuit (arc insertion diameter) to insert the cutter.

The typical parameter is 1500 RPM and 61 ipm. Each time the tool inserts 4 inches in diameter, it performs a 0. The 6 inch spiral. For each lap of 0.06 inches, approximately 50 pass holes will be required, plus 5 passes to the center line of the circular insertion.

Diameter of each aperture is equal to 4 inch aperture and 2 inch diameter, or 2 inches. The total distance traveled by the tool is equal to the product of 55 lines, times 6.28 inches (2 inches in diameter round circumference), or 345 inches. At 61 ipm, the time to feed this distance is about 5.5 minutes.

In other words, in this example, the spiral interpolation is reduced by 87% in the cycle. It also eliminates a tool.

The intensity of edge

end mill for stainless steel